How to find consecutive numbers

So i have an array: a=[16 17 32 33 48 63 79 80 81 97 98 113 114 129 130]

how can i write a program to find where those consecutive numbers are? i've tried using a for loop but haven't really got anywhere.. Please note that at one point there is 3 consecutive numbers.. The idea is each of these numbers is an index of another array: value=[3 0 2 5 3 2 1 0 0 2 7 7 3 7 8]; all equally spaced, which is supposed to mean: realvalue=[30 25 3 2 100 27 73 78]; and im trying to get the array 'realvaue' from arrays 'a' and 'value'

Answer 1

[Thomas]

diff(a)==1

should do the job for you. It will show you where in a you have consecutive values..

a(diff(a)==1)

Gives the first value

or

p=find(diff(a)==1)
q=[p;p+1];
a(q)  % this gives all the pairs of consecutive numbers

[ping pong]

working,its good

Answer 2

[Andrei Bobrov]

i1 = 1;
C{i1}=a(i1);
for j1 = 2:numel(a)
    t = a(j1)-a(j1-1);
    if t == 1
        C{i1} = [C{i1} a(j1)];
    else
        i1  = i1 + 1;
        C{i1} = a(j1);
    end
end

OR

k= find(diff(a)==1);
k1 = [k;k+1];
idx = reshape(k1(k1~=intersect(k,k+1)),2,[]);
C = arrayfun(@(x)a(idx(1,x):idx(2,x)),1:size(idx,2),'un',0)

ADD

i1 = 1;
C(1)=1;
for j1 = 2:numel(a)
    t = a(j1)-a(j1-1);
    if t == 1
        C(i1) = C(i1) + 1;
    else
        i1  = i1 + 1;
        C(i1) = 1;
    end
end

v = [3 0 2 5 3 2 1 0 0 2 7 7 3 7 8]; 
rv = str2double(mat2cell(sprintf('%d',v),1,C))

OR

k= find(diff(a)==1);
k1 = [k;k+1];
idx = reshape(k1(k1~=intersect(k,k+1)),2,[]);
id = sortrows([idx ones(2,1)*setdiff(1:numel(a),k1(:))].',1).';
C = diff(id)+1;

v = [3 0 2 5 3 2 1 0 0 2 7 7 3 7 8];
rv = str2double(mat2cell(sprintf('%d',v),1,C));

Last added

realvalue = accumarray(cumsum([true diff(a) ~= 1])',value',[],@(x)str2double(sprintf('%d',x')))

new add 2016

t = diff(a) == 1;
y = [t,false];
x = xor(y,[false,t]);
ii = cumsum(~(x|y) + y.*x);
out = accumarray(ii(:),value(:),[],@(z)10.^(numel(z)-1:-1:0)*z);

[Arun Badigannavar]

Does this work on simulink. parameters? what would be the best way to compare consecutive numbers in simulink dd?

[yeungor]

Andrei definitely seems like a code golfer. Thanks for this, I'm using it to find linear regions in data.

Answer 3

[Adil Sbai]

Call this function:

function bool = successive(a)
% Determines if all the numbers in a given input 1D array are successive
% integers. 
% 

      assert((size(a,1)==1 || size(a,2)==1) && isa(a,'double'));

      a = sort(a);
      bool = (abs(max(a)-min(a))+1)==numel(a);

end

These are examples:

>> successive([-1 4 3 0 2 1])

ans =

       1
  >> successive([-1 4 3 -3 2 1])

ans =

       0