Function handle as function input?

Hello there, I have a function handle, for example f = @(x) x.^2 and I want to use this as a function input, something like (just schematic):

function scalar = fct(f(x));
scalar = int(@(x) f(x).*x^2);
end

Is that possible? Greets and thanks!

[Star Strider]

CONTEXT: Pass 'function handle' to another 'function handle'? (link)

Answer 1

[Rik]

Inside such a wrapper, I highly doubt that. But in principle it should be possible to do what you want. I haven't tested this code, but I think this should work. (After a peek at the doc for int, I suspect this would error, but the principle should hold, after all, f is just a variable, even if it is a weird variable because it is an anonymous function)

function scalar=fct(f)
temp=@(x) f(x).*x.^2;
scalar=int(temp);
end

[Payjay]

Thank you! Unfortunately this does not work, tried it before..

[Rik]

What exactly is the error you are getting here? Because as I understand it, int needs more inputs if the first input does not contain a symbolic variable. So is the problem occurring at the function call level, or inside the function fct?

[Payjay]

I am sorry youre answer worked! Thanks! And that what I wrote down above even works too! I have thousands nested functions and I understood the errors wrong ;-)