Could anyone shed some light on how this 'for' loop can be replaced by a single command in MATLAB?
for i=1:size(w,3)
x=w(:,:,i);
w1(i,:)=x(B(i),:);
end
clear x
Here, w is 3D (x by y by z) matrix and B (1 by z) is a vector containing rows pertaining to each layer in w. This 'for' loop takes about 150 seconds to execute when w is 500000 layers deep. I tried using,
Q = w(B,:,:);
Q = reshape(Q(1,:),[500000,2])';
This creates a matrix Q of size 500000 X 2 X 500000 and MATLAB threw me an error saying memory out of bound. Any help would be appreciated!

 채택된 답변

Roger Stafford
Roger Stafford 2017년 5월 18일

1 개 추천

It is important for efficiency’s sake that you initially allocate a sufficient amount of space for the w1 array before entering the for-loop:
[~,n2,n3] = size(w);
w1 = zeros(n3,n2); % <-- Initial memory allocation
for i=1:n3
w1(i,:)=w(B(i),:,i);
end

댓글 수: 1

Vijay
Vijay 2017년 5월 18일
Thank you very much for the answer! Cheers!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2017년 5월 18일

댓글:

2017년 5월 18일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by