How can I sort a Map by values ?

For the example below, how can I sort the mapObj by values and of course the keys must also folow the valeus new order.
keySet = {'Jan', 'Feb', 'Mar', 'Apr'};
valueSet = [327.2, 368.2, 197.6, 178.4];
mapObj = containers.Map(keySet,valueSet);

댓글 수: 5

Adam
Adam 2017년 5월 3일
containers.Map is an unsorted data structure. You can sort the values and keys if you extract them, but you cannot sort the map itself, it will always return the keys and values ordered alphanumerically by key.
KL
KL 2017년 5월 3일
Thanks for the comment Adam, I removed my answer.
sendja450
sendja450 2017년 5월 4일
thanks for your comments, if I want to extract theme I will lose the (key, value) property. So how can I extract in a for loop the max in each iteration in order to have a descending order ?
Adam
Adam 2017년 5월 5일
편집: Adam 2017년 5월 8일
You can extract the keys and the values and do a sort on the keys, making sure to retain the 2nd output argument from sort - these are the indices required to apply to the values in order for them to be ordered to match the keys still e.g.
keys = myMap.keys;
values = myMap.values;
[sortedKeys, sortIdx] = sort( keys );
sortedValues = values( sortIdx );
sendja450
sendja450 2017년 5월 7일
Thanks for your help @Adam.

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답변 (1개)

KUNHUAN
KUNHUAN 2023년 4월 11일

0 개 추천

IDEA
One way is to retrieve keys and values and sort them independently.
First, sort values. Then, sort keys. Lastly, reassign keys and values.
Using flip to sort in reverse order.
IMPLEMENTATION
keySet = {'Jan', 'Feb', 'Mar', 'Apr'};
valueSet = [327.2, 368.2, 197.6, 178.4];
mapObj = containers.Map(keySet,valueSet);
[mapObj, keys_map, values_map] = sort_map(mapObj) % Default: order="values", reverse=0
mapObj =
Map with properties: Count: 4 KeyType: char ValueType: double
keys_map = 1×4 cell array
{'Apr'} {'Mar'} {'Jan'} {'Feb'}
values_map = 1×4
178.4000 197.6000 327.2000 368.2000
[mapObj, keys_map, values_map] = sort_map(mapObj, order="keys", reverse=1)
mapObj =
Map with properties: Count: 4 KeyType: char ValueType: double
keys_map = 1×4 cell array
{'Mar'} {'Jan'} {'Feb'} {'Apr'}
values_map = 1×4
197.6000 327.2000 368.2000 178.4000
Define the following sort_map function.
function [output, keys_map, values_map] = sort_map (input, options)
arguments
input containers.Map;
options.order char = "values";
options.reverse logical = 0;
end
k = keys(input);
v = cell2mat(values(input));
% Default return
output = input;
keys_map = k;
values_map = v;
if (options.order == "keys")
[k_new, order] = sort(k);
if (options.reverse == 1)
k_new = flip(k_new);
order = flip(order);
end
v_new = v(order);
output = containers.Map(k_new, v_new);
keys_map = k_new;
values_map = v_new;
elseif (options.order == "values")
[v_new, order] = sort(v);
if (options.reverse == 1)
v_new = flip(v_new);
order = flip(order);
end
k_new = k(order);
output = containers.Map(k_new, v_new);
keys_map = k_new;
values_map = v_new;
end
end
REFERENCES
There is a section that introduces sorting with the same order:
% X = [3 6 4 2 1 5];
% Y = ["yellow" "purple" "green" "orange" "red" "blue"];
% [Xsorted,I] = sort(X)
% Ysorted = Y(I)

댓글 수: 1

Stephen23
Stephen23 2023년 4월 11일
편집: Stephen23 2023년 4월 11일
"Lastly, reassign keys and values" does nothing.
As Adam explained six years ago here, containers.Map is an unsorted data type, so this code makes absolutely no difference to the order of the keys and values of the containers.Map objects themselves:
keySet = {'Jan', 'Feb', 'Mar', 'Apr'};
valueSet = [327.2, 368.2, 197.6, 178.4];
mapObj0 = containers.Map(keySet,valueSet);
mapObj0.keys
ans = 1×4 cell array
{'Apr'} {'Feb'} {'Jan'} {'Mar'}
mapObj0.values
ans = 1×4 cell array
{[178.4000]} {[368.2000]} {[327.2000]} {[197.6000]}
mapObj1 = sort_map(mapObj0); % Default: order="values", reverse=0
mapObj1.keys
ans = 1×4 cell array
{'Apr'} {'Feb'} {'Jan'} {'Mar'}
mapObj1.values
ans = 1×4 cell array
{[178.4000]} {[368.2000]} {[327.2000]} {[197.6000]}
mapObj2 = sort_map(mapObj0, order="keys", reverse=1);
mapObj2.keys
ans = 1×4 cell array
{'Apr'} {'Feb'} {'Jan'} {'Mar'}
mapObj2.values
ans = 1×4 cell array
{[178.4000]} {[368.2000]} {[327.2000]} {[197.6000]}
function [output, keys_map, values_map] = sort_map (input, options)
arguments
input containers.Map;
options.order char = "values";
options.reverse logical = 0;
end
k = keys(input);
v = cell2mat(values(input));
% Default return
output = input;
keys_map = k;
values_map = v;
if (options.order == "keys")
[k_new, order] = sort(k);
if (options.reverse == 1)
k_new = flip(k_new);
order = flip(order);
end
v_new = v(order);
output = containers.Map(k_new, v_new);
keys_map = k_new;
values_map = v_new;
elseif (options.order == "values")
[v_new, order] = sort(v);
if (options.reverse == 1)
v_new = flip(v_new);
order = flip(order);
end
k_new = k(order);
output = containers.Map(k_new, v_new);
keys_map = k_new;
values_map = v_new;
end
end

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도움말 센터File Exchange에서 Shifting and Sorting Matrices에 대해 자세히 알아보기

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2023년 4월 11일

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