Comparing matrices of different size in matlab and storing values that are close

I have two matrices A and B. A(:,1) corresponds to an x-coordinate, A(:,2) corresponds to a y-coordinate, and A(:,3) corresponds to a certain radius. All three values in a row describe the same circle. Now let's say...

A =

[1,4,3]

[8,8,7]

[3,6,3]

B =

[1,3,3]

[1, 92,3]

[4,57,8]

[5,62,1]

[3,4,6]

[9,8,7]

What I need is to be able to loop through matrix A and determine if there are any rows in matrix B that are "similar" as in the x value is within a range (-2,2) of the x value of A (Likewise with the y-coordinate and radius).If it satisfies all three of these conditions, it will be added to a new matrix with the values that were in A. So for example I would need the above data to return...

ans =

[1,4,3]

[8,8,7]

Please help and thank you in advance to anyone willing to take the time!

[Will Nitsch]

The following will scan through B, comparing each portion of A and B. If the criteria is met, then it will store the indices of the matching (within the range +/-2) values of A and B.

A = [[1,4,3];[8,8,7];[3,6,3]];

B = [[1,3,3];[1, 92,3];[4,57,8];[5,62,1];[3,4,6];[9,8,7]];

idx = [];

   for i = 1:length(A)
       for j = 1:1:length(B)
         if(find(B(abs(B(j,1)-A(i,1))<=2 & abs(B(j,2)-A(i,2))<=2 & abs(B(j,3)-A(i,3))<=2)==1))
             idx = [idx,[i;j]]; 
         end
       end
   end

output:

idx =

     1     2  % these are the indicies of A
     1     6  % these are the corresponding indices of B