Why does this appear as empty?

I want to create a from 200 to -300 with the direction going down by 2. I also want to skip the numbers from 197 to -298 with some dots. So it would look something like this:

I =

200

198

.

.

.

.

-298

-300

I understand I first have to start with I:(200:-300)' But it always come up as 0×1 empty double column vector

I also can't remember how the numbers can be counted by 2 AND skip from 198 to -298. Any help would be appreciated

[James Tursa]

Do you mean you are trying to display the vector this way? Even though it contains all of the intermediate numbers? Or what?

[Seong Nam]

Yes, that's what I meant

Answer 1

[Image Analyst]

You say "I want to create a" but then you later create and use I. You say "skip the numbers from 197 to -298" but then your expected results actually include -298. Anyway, ignoring those discrepancies, I came up with this:

a = (200 : -2 : -300)';  % Or use I instead of a.
for k = 1 : length(a)
  if a(k) <= 197 && a(k) > -298 % or >= -298
    fprintf('.\n');
  else
    fprintf('%d\n', a(k));
  end
end

Answer 2

[Walter Roberson]

The basic issue is that when you have A:B and B < A, then the result will always be empty. The default increment is always 1. If you want to decrement, then you need to specify a negative increment, such as 200:-2:-300 .

The alternative is to use

   fliplr(-300:2:200)