필터 지우기
필터 지우기

Replace the indexes of duplicate values

조회 수: 1 (최근 30일)
Yesbol
Yesbol 2017년 4월 24일
답변: RST 2024년 5월 14일
I have a matrix B 1631x5.
Columns 2 and 3 represent X and Y coordinates respectively.
I want to identify the indexes where B(i+k,2)==B(i+j,2)&B(i+k,3)==B(i+j,3). Note that there can be more than one duplicate.
Below is the script of identifying the duplicates:
%%X coordinate
[~, indX] = unique(B(:, 2), 'rows');
% duplicate indices
duplicate_indX = setdiff(1:size(B, 1), indX);
% duplicate values
duplicate_valueX = B(duplicate_indX, 2);
%%Y coordinate
[~, indY] = unique(B(:, 3), 'rows');
% duplicate indices
duplicate_indY = setdiff(1:size(B, 1), indY);
% duplicate values
duplicate_valueY = B(duplicate_indY, 3);
%%Both coordinates
duplicate_ind=intersect(duplicate_indX,duplicate_indY);
duplicate_value = B(duplicate_ind, 2:3);
When the code is executed, we get 2 matrix: duplicate_ind(1x149) and duplicate_value(149x2).
Let's consider first 4 values of duplicate_ind as an example:
>> duplicate_ind(1:4)
ans =
61 77 106 111
The corresponding values for these indexes are
>> duplicate_value(1:4,:)
ans =
355.3035 176.9755
364.7316 182.2644
354.4987 202.1553
350.5895 226.7602
Now I can find the original and the duplicate:
find(B(:,2)==duplicate_value(1,1))
ans =
1
61
>> find(B(:,2)==duplicate_value(2,1))
ans =
57
77
In this case, the index of the original value is 1 and the index of duplicate is 61. In other case: original: 57 and duplicate:77.
Now, I want to replace the indexes of the duplicates by the original ones. In our case 61 will be replaced by 1 (and 77 will be replaced by 57). Considering above, I want to build a matrix which has the size 1631x3 (must have the same number of rows as matrix B), where the 1st row represents the line number, 2nd and 3rd row - the coordinates of points.
The output is expected to look like:
1 1 2
2 2 3
3 3 4
...
57 57 58
...
61 1 62
...
77 57 78
78 78 79
...

채택된 답변

Yesbol
Yesbol 2017년 4월 24일
Solved
%%X coordinate
[~, indX] = unique(B(:, 2), 'rows');
% duplicate indices
duplicate_indX = setdiff(1:size(B, 1), indX);
% duplicate values
duplicate_valueX = B(duplicate_indX, 2);
%%Y coordinate
[~, indY] = unique(B(:, 3), 'rows');
% duplicate indices
duplicate_indY = setdiff(1:size(B, 1), indY);
% duplicate values
duplicate_valueY = B(duplicate_indY, 3);
%%Both coordinates
duplicate_ind=intersect(duplicate_indX,duplicate_indY);
duplicate_value = B(duplicate_ind, 2:3);
indexes=zeros(3,size(duplicate_value,1));
for i=1:size(duplicate_value,1)
if size(find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2)),1)==2
indexes(1:2,i)=find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2));
end
if size(find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2)),1)==3
indexes(1:3,i)=find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2));
end
end
for j=1:size(B,1)-1
lines(j,1:2)=j;
lines(j,3)=j+1;
end
for j=1:size(lines,1)
for i=1:1:size(indexes,2)
if indexes(3,i)==0
if lines(j,2)==indexes(2,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(2,i)
lines(j,3)=indexes(1,i);
end
end
if indexes(3,i)~=0
if lines(j,2)==indexes(3,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(3,i)
lines(j,3)=indexes(1,i);
end
if lines(j,2)==indexes(2,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(2,i)
lines(j,3)=indexes(1,i);
end
end
end
end

추가 답변 (1개)

RST
RST 2024년 5월 14일
Try this:
[~,ixu,ixb] = unique(B(:,2:3),'rows'); % indices of unique rows for columns 2 and 3
ixd = setdiff(1:size(B,1), ixu); % (duplicate rows) = (all rows) - (unique rows)
fprintf("There are %d duplicate points\n", numel(ixd))
% make a copy of the data
C = B;
% for each duplicate
for iixd=ixd
% get indices of the matching rows
% fd = find( all(B(:,2:3)==B(iixd,2:3), 2) );
fd = find(ixb == ixb(iixd));
% overwrite 2nd and subsequent matching rows with the first
C(fd(2:end),:) = repmat( B(fd(1),:), ...
numel(fd)-1, 1);
end
clear fd, iixd, ixd, ixb, ixu

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by