How to get the original rgb image from hsv image?
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OK, so I have this image(in HSV) which i have got after cropping:
Now,I want to implement the same dimension cropping(i.e. the image width and height should be same as the above image) to my original(uncropped)rgb image,which is:
I used the following code
img1=imread('2.jpg');%this is the original rgb image
[y1,x1] = find(img1);
xmin1 = min(x1(:));
ymin1 = min(y1(:));
xmax1= max(x1(:));
ymax1 = max(y1(:));
width1=xmax1-xmin1+1;
height1=ymax1-ymin1+1;
img2=imread('cropbin1.jpg');%this is the HSV image
[y2,x2] = find(img2);
xmin2 = min(x2(:));
ymin2 = min(y2(:));
xmax2= max(x2(:));
ymax2 = max(y2(:));
width2=xmax2-xmin2+1;
height2=ymax1-ymin2+1;
w3=(width1-width2)/2;
h3=(height1-height2)/2;
out = imcrop(img1,[w3 h3 width2 height2]);
figure,imshow(out);
But, to my horror, the output is showing no image.
Please help.
I would like my original image to be like:
Please suggest any other way by which I can change the HSV image to a rgb image. Thanxxx.......
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Image Analyst
2017년 4월 9일
There are so many things wrong with that code, that it's just faster to give you whole new code than to explain it to you. In the meantime, I fixed your formatting but for the future, please read this: http://www.mathworks.com/matlabcentral/answers/13205#answer_18099
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Image Analyst
2017년 4월 9일
See attached solution.
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Image Analyst
2017년 4월 9일
Not it won't. Just look at it:
xmin1 = min(x1(:));
well x1 is the number of columns multiplied by the number of color channels (3). Why? Just read http://blogs.mathworks.com/steve/2011/03/22/too-much-information-about-the-size-function/ So x1 is 12,960, NOT the number of columns in the image. It's not even an array, so doing this: x1(:) will not do what you thought it did. Lots more problems after that.
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