I have an array
a=[0 0 1 0 ; 1 2 3 0; 1 0 3 4; 0 2 0 0 ]
& cell array like
b{1,1}=[4;3]
b{2,1}=[3;1;4]
I want to find elements of cell array in a. For example: for b{2,1} 1st, 3rd and 4th row of a should be displayed and 2nd should be zero.
Thanks in advance

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Andrei Bobrov
Andrei Bobrov 2017년 4월 4일

0 개 추천

a=[0 0 1 0 ; 1 2 3 0; 1 0 3 4; 0 2 0 0 ];
b{1,1}=[4;3];
b{2,1}=[3;1;4];
v = 1:size(a,1);
t = cell2mat(cellfun(@(x)ismember(v,x),b,'un',0))';
out = a.*permute(t,[1,3,2]);

댓글 수: 7

lucksBi
lucksBi 2017년 4월 4일
Thank you so much. This is exactly what i want. Can I get final result in cell array other than 3D array?
Yes.
a=[0 0 1 0 ; 1 2 3 0; 1 0 3 4; 0 2 0 0 ];
b{1,1}=[4;3];
b{2,1}=[3;1;4];
out = cellfun(@(x)a.*ismember((1:size(a,1))',x),b,'un',0);
lucksBi
lucksBi 2017년 4월 5일
Thanks alot
lucksBi
lucksBi 2017년 4월 5일
It is working fine on small matrix e.g i tried on 6x6 matrix size it is giving accurate results. But when i tried it on matrix of size 943x943, it gives following error. ??? Error using ==> times Matrix dimensions must agree.
Error in ==> @(x)a.*ismember((1:size(a,1))',x) Error in ==> file2 at 22 out=cellfun(@(x)a.*ismember((1:size(a,1))',x),b,'un',0);
can you please help on this.
Andrei Bobrov
Andrei Bobrov 2017년 4월 5일
Please attach your data that gives an error.
lucksBi
lucksBi 2017년 4월 5일
here are .mat files of a & b matrices
lucksBi
lucksBi 2017년 4월 17일
hey can you please help on this matter? i am unable to fix this issue with with given mat files.

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추가 답변 (1개)

Thorsten
Thorsten 2017년 4월 4일

0 개 추천

idx = cellfun(@(x) any(ismember(a, x)), b, 'UniformOutput', false);
rows = cellfun(@(x) a(:, x), idx, 'UniformOutput', false);
Or in one line:
rows = cellfun(@(x) a(:, any(ismember(a, x))), b, 'UniformOutput', false);

댓글 수: 3

lucksBi
lucksBi 2017년 4월 4일
Thanks Alot. But it gives 4x2 array for b{1,1}, (changes no of columns in each cell) i want a 4x4 array with elements of rows that are member of b and other rows as zero.
Like this?
idx = cellfun(@(x) any(ismember(a, x)), b, 'UniformOutput', false);
a0 = zeros(size(a));
for i = 1:numel(idx)
rows{i} = a0;
rows{i}(:,idx{i}) = a(:,idx{i});
end
lucksBi
lucksBi 2017년 4월 4일
result should be like: result{1,1}= [0,0,0,0;0,0,0,0;1,0,3,4;0,2,0,0] result{1,2}= [0,0,1,0;0,0,0,0;1,0,3,4;0,2,0,0]

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도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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2017년 4월 4일

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2017년 4월 17일

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