필터 지우기
필터 지우기

why color fringes are not deformed by peak function?

조회 수: 2 (최근 30일)
ajeet verma
ajeet verma 2017년 3월 27일
댓글: KSSV 2017년 3월 27일
i have a code in which fringe pattern is projected on the 3D object(peaks) and fringes are deformed according to peaks. code is--
m=1000;
n=1000;
%object
[x,y,z]=peaks;
z=imresize(z,[m,n]);
Q=exp(1i*z*1);
subplot(2,3,1),imshow(z,[])
%sinusoidal fringes
f1=30;
f2=0;
for i = 1:m
for j=1:n
a(i,j)=exp(1i*2*pi*(f1*j/n+f2*i/m));
end
end
V=128*(real(a)+1);
subplot(2,3,2),imshow(V,[])
%modulation
U=128*(real(a.*Q)+1);
subplot(2,3,3),imshow(U,[])
but when color fringe patterns are projected, these are not deformed but i need . code is given
%color fringe projection
m=1000;
n=1000;
% object
[x,y,z]=peaks;
z=imresize(z,[m,n]);
Q=exp(1i*z*2);
subplot(331),imshow(z,[]),impixelinfo;
% color fringes
f1=20; % No. of vertical fringes
f2=0; % No. of horizontal fringes
a1 = zeros(m,n) ;
a2 = zeros(m,n) ;
a3 = zeros(m,n) ;
for i=1:m
for j=1:n
a1(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)-2*pi/3));
a2(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)));
a3(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)+2*pi/3));
end
end
Color=zeros(m,n,3);
Color(:,:,1)=a1;
Color(:,:,2)=a2;
Color(:,:,3)=a3;
%imshow(Color,[]),impixelinfo;
imwrite(Color,'myimage1.jpg');
% seperation into r,g,b component
i = imread('myimage1.jpg'); % Read image
red = double(i(:,:,1)); % Red channel
green = double(i(:,:,2)); % Green channel
blue = double(i(:,:,3)); % Blue channel
%a = zeros(size(i, 1), size(i, 2));
%R = cat(3, red, a, a);
%G = cat(3, a, green, a);
%B = cat(3, a, a, blue);
subplot(332),imshow(red,[]);
subplot(333),imshow(green,[]);
subplot(334),imshow(blue,[]);
% projection
R=real(red.*Q);
G=real(green.*Q);
B=real(blue.*Q);
subplot(335),imshow(R,[]);
subplot(336),imshow(G,[]);
subplot(337),imshow(B,[]);
so help me please and tell me what is wrong ?
  댓글 수: 1
KSSV
KSSV 2017년 3월 27일
You check your folder.....a .jpg file is created on the name myimage1.jpg this is the colored image.

댓글을 달려면 로그인하십시오.

답변 (0개)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by