While loop - display the last value while statement is still true

조회 수: 4 (최근 30일)
astein
astein 2017년 3월 20일
댓글: astein 2017년 3월 24일
The example given on Mathworks doesn't make sense to me.
x=0
p=1-poisscdf(1,x);
while p<=0.1
x=x+0.01;
p=1-poisscdf(1,x);
end
display(x);
The x value given at the end of the loop is the first value that makes the statement false.What can I add to the script so that display(x) gives me the last value that makes the statement true?
*Edit:
I just tried:
x=0;
p=1-poisscdf(1,x);
while p2more<=0.1
x=x+0.01;
p=1-poisscdf(1,x);
if p>=0.1
break
end
display(x);
end
Now I get all the values of x where this statement is true. I just want the last value. :X

채택된 답변

James Tursa
James Tursa 2017년 3월 21일
편집: James Tursa 2017년 3월 21일
You could just use another variable. E.g., y
x=0
p=1-poisscdf(1,x);
while p<=0.1
y = x; % <-- save current value of x
x=x+0.01;
p=1-poisscdf(1,x);
end
display(y); % <-- display last value of x for which test was true
  댓글 수: 3
James Tursa
James Tursa 2017년 3월 24일
Right after the test passes, you save the x value that made the test pass. But when you generate an x value that doesn't pass the test, you don't execute the y = x statement. So it is only the x values that pass the test that are saved in y. And the last one is what makes it to the display(y) statement.
astein
astein 2017년 3월 24일
Thank you, that was really helpful.

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추가 답변 (1개)

Jan
Jan 2017년 3월 21일
편집: Jan 2017년 3월 21일
The trivial soultion is:
x = 0;
p = 1 - poisscdf(1, x);
while p <= 0.1
x = x + 0.01;
p = 1 - poisscdf(1, x);
end
x = x - 0.01;
display(x);
If the increasing of x is not a constant:
x = 0;
lastx = x;
p = 1 - poisscdf(1, x);
while p <= 0.1
lastx = x;
x = x + 0.01;
p = 1 - poisscdf(1, x);
end
display(lastx);
Now p is defined twice and redundacies in the code are prone to bugs: If one instance is modified later, that other might be forgotton. To avoid this:
x = 0;
ready = false
while ~ready
p = 1 - poisscdf(1, x);
ready = (p < 0.1);
lastx = x;
x = x + 0.01;
end
display(lastx);

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