Array operations

How can I solve this problem using MATLAB? The array n is all integers from 1 to 110. The array y is defined by: y= n^(1/2) if n is divisible by 3, 5, or 7 y= 0 otherwise Find the value of the sum of the elements of y.

[James Tursa]

What code have you written so far? Which parts are you stuck on?

[Aldin]

I can't understand is n these numbers:

ans =

Columns 1 through 18

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

Columns 19 through 36

19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36

Columns 37 through 54

37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54

Columns 55 through 72

55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72

Columns 73 through 90

73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90

Columns 91 through 108

91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108

Columns 109 through 110

109 110

or random generated

[James Tursa]

Yes, n is those numbers.

[Andrei Bobrov]

out = sum(sqrt(num(all(bsxfun(@rem,num.',[3 5 7]),2))))

Answer 1

[yasmine]

num = 1:110;

for i = 1:101 z(i) = num(i)/3; x(i)= num(i)/5; y(i)= num(i)/7;

if rem(z(i),1) == 0; k(i) = num(i)^(1/2);

elseif rem(x(i),1) == 0; k(i) = num(i)^(1/2);

elseif rem(y(i),1) == 0; k(i) = num(i)^(1/2);

else k(i) = 0;

end;

end;

sum = sum(k);

[Yassine]

thanks for the answer, but what does '1' mean in the expression rem(Z(i),1)?

[Jan]

Please read the documentation: type "help rem" in the command window.

Answer 2

[Jan]

Start with:

n = 1:110;

Now remember that ^(1/2) is the squareroot.

How can you check, if the numbers in a vector can be divided by 3, 5, or 7? Look e.g. in the help for rem:

doc rem

Another idea:

x = 1:3:20

...