how i can vectorize this code using bsxfun or meshgrid?

Hi,
I am trying to vectorize this code, but I dont know how to start it, I read the help files for both bsxfun and meshgrid but no luck. Can someone please guide how to look at this rather than giving the code. My code is working for me but i want to improve it.
s1= 50;
s2=100;
E_=zeros(s2,s2);
grid_=linspace(-2.5,2.5,s2);
tau=linspace(-pi,pi,s1);
x=cos(tau);
y=sin(tau);
cur=myfun(x,y); %returns vector
for k=1:s2
for m=1:s2
for n=1:s1
R= abs(sqrt((grid_(m)-x(n))^2+(grid_(k)-y(n))^2));
u_(n)= besselj(0,R)*cur(n);
end
E_(k,m)=abs(trapz(tau,u_));
end
end
Thanks
Turker

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Jan
Jan 2017년 3월 14일
편집: Jan 2017년 3월 15일
You can replace the inner loop by:
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2)); % [EDITED]: ^ to .^
u_ = besselj(0, R) .* cur;
I guess, that the abs() is not required.

댓글 수: 4

Thanks Jan, x and y are array. And I a calculating the distance between points one by one. When we change it like this, does R become an array?
Jan
Jan 2017년 3월 15일
편집: Jan 2017년 3월 15일
Yes, R has the same size as x and y, and u_ has also. At least if you run the improved version which uses the elementwise squaring .^2. See [EDITED]
Hi Jan, it returns error as;
Assignment has more non-singleton rhs dimensions than
non-singleton subscripts
Error in testfields (line 121)
E_(k,m)=abs(trapz(tau,u_));
ttopal
ttopal 2017년 3월 16일
편집: ttopal 2017년 3월 16일
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2))'; %transpoze added.
u_ = besselj(0, R) .* cur;
Now it works! Thank you Jan!

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2017년 3월 14일

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