pop1h generate 10 random number from 200 to 1150 now need to check this answer pop=pop1h*2 if this answer is<500 than not valid again new 10 digit generate and do same process untill condition satisfy
check answer in range otherwise do again process with random generated number check until all digit of loop in range
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for k1=1:10 %set population generation limit her
pop1h(k1)=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
end
pop=pop1h*2
if pop<500;
break
else
continue
end
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KSSV
2017년 3월 10일
for k1=1:100 %set population generation limit her
pop1h=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
pop=pop1h*2 ;
if pop<500;
disp('condition satisfied loop exited') ;
break
else
continue
end
end
댓글 수: 7
KSSV
2017년 3월 10일
count = 0 ;
N = 10 ;
iwant = zeros(N,1) ;
for k1=1:100 %set population generation limit her
pop1h=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
pop=pop1h*2 ;
if pop > 500;
count = count+1 ;
iwant(count) = pop ;
if count == N
break
end
else
continue
end
end
This can be achieved without loop also
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