How do I add commas to numbers using fprintf?
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Hello,
How do I add commas to numbers using fprintf? My customer wants me to write out tables and have commas in the numbers to better read it. For instance, 123456789.0 would be written out as 123,456,789.0. Thanks.
Best regards,
Bill Rooker
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채택된 답변
  Stephen23
      
      
 2017년 3월 8일
        
      편집: Stephen23
      
      
 2023년 9월 15일
  
      fprintf cannot do that, but you will find several FEX submissions that can create a string with commas as thousands separators:
If you read the comments to those submissions you will also find several improvements to consider.
Another easy one-line approach:
str = ["1234567890.123456789";"-1234567890";"0"]
str = regexprep(str,'(?<!\.\d*)\d{1,3}(?=(\d{3})+\>)','$&,')
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  Stephen23
      
      
 2023년 9월 15일
				
      편집: Stephen23
      
      
 2023년 9월 15일
  
			The only resources I really use are the MATLAB documentation:
etc.
You can find some online tutorials etc that explain regular expression concepts** but these often are based on Perl or JavaScript or Python or whatever regular expressions (i.e. not the same details) so once you really need to know the details then the only place to look is the MATLAB documentation. Be prepared to read those pages many times.
If you want to experiment then you might find this useful:
** as well as many websites offering all kinds of automagic things with regular expressions.
  Dyuman Joshi
      
      
 2023년 9월 16일
				I tried working with the documentation pages of regexp() and regexprep(), but haven't been successful with it, as they are not clear/specific enough to me and do not provide sufficient examples to understand the functionality properly.
Thank you very much for the links, I didn't know about these pages, they are what I was looking for!
I have also tried a few online tutorials, but as you mentioned, the functionality of regexp() in other languages are different than in MATLAB.
I will also look into the FEX submission you have link, it does look very extensive, but for now, I will start from the basics with the documentation pages you linked.
Once again, Thank you!
추가 답변 (4개)
  Ted Shultz
      
 2018년 6월 13일
        function numOut = addComma(numIn)
   jf=java.text.DecimalFormat; % comma for thousands, three decimal places
   numOut= char(jf.format(numIn)); % omit "char" if you want a string out
end
Hope that helps! --ted
댓글 수: 5
  Daven Gooden
 2020년 11월 10일
				@Ted Shultz: Spot on! Very clean and easy to understand/use!  Thank you very mutch!
  Jim Svensson
      
 2021년 2월 15일
        I feel that in 2021 this functionality should be supported by sprintf/fprintf.
댓글 수: 3
  Dyuman Joshi
      
      
 2023년 9월 15일
				@Jim Svensson If you want to have a functionality implemented in MATLAB, you can raise a feature request for it.
I believe you will need a strong justification to convince TMW as to why they should implement it.
  Image Analyst
      
      
 2023년 9월 16일
				It would certainly be a convenience if they had a letter to do that conversion, like p or whatever (some unused letter), like
x = 12345678.912345
fprintf('Number = %p.\n', x);
'12,345,678.912'
  Image Analyst
      
      
 2023년 9월 15일
        See my attached utility function that inserts commas to make a string out of a number.  Then in your fprintf you print the string with %s instead of %d or %f.  For example:
number = 1234567;
fprintf('The number is %s.\n', CommaFormat(number));
댓글 수: 0
  Toshiaki Takeuchi
    
 2023년 11월 14일
        Using pattern
vec = 123456789;
txt = string(vec);
pat1 = lookBehindBoundary(digitsPattern); % (?<=\d)
pat2 = asManyOfPattern(digitsPattern(3),1); % (\d{3})+
pat3 = lookAheadBoundary(pat2+lineBoundary("end")); % (?=(\d{3})+$)
pat4 = pat1+pat3; % (?<=\d)(?=(\d{3})+$)
replace(txt,pat4,",") 
댓글 수: 1
  Stephen23
      
      
 2023년 11월 14일
				vec = 1234.56789
txt = string(vec);
pat1 = lookBehindBoundary(digitsPattern); % (?<=\d)
pat2 = asManyOfPattern(digitsPattern(3),1); % (\d{3})+
pat3 = lookAheadBoundary(pat2+lineBoundary("end")); % (?=(\d{3})+$)
pat4 = pat1+pat3; % (?<=\d)(?=(\d{3})+$)
replace(txt,pat4,",") 
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