How to Assign Values from a Struct to a Matrix in a For Loop?

A.B.C = [1 2 3];
A.B.D = [3 4 5]; 

for k = 1:2
G(k, :) = A.B.C;
G(k, :) = A.B.D;
end
G

G returns:

3     4     5
3     4     5

Why doesn’t it return the following? What is the solution to have a G like the following?

    1     2     3
    3     4     5

Answer 1

[Walter Roberson]

G(1,:) = A.B.C;
G(2,:) = A.B.D;

No loop.

[Rightia Rollmann]

What if instead of two fields, I had 50 fields?

Isn't there any way to use a for loop to dynamically make a matrix out of vectors stored in a struct?

[Walter Roberson]

G = cell2mat( struct2cell(A.B) );