How do I find the base of a right angle triangle b=xcos(a) in matlab.

('x' has to be a positive value and 'a' has to entered in degrees then converted to radian)

[KSSV]

It is such simple....there is inbuilt function cos . Read about it.

Answer 1

[Andres Yie]

Use the comands:

    a = input('Enter a in radians')
    x = input('Enter x') 
    a = rad2deg(a)  %Converts to degrees
    b = x*cosd(a);

Also you can skip the radinas and use the cos() function that accepts the argument in radians.

[Walter Roberson]

I think the intent was more

a = input('Enter a in degrees');
x = input('Enter x');
b = x*cosd(a);