Determining the second last row

Hi there,

How would you code the number of rows minus one? Below I use size() to find the number of rows, but I want to set nrows to the number or rows minus 1.

Many thanks

sch_cycle=xlsread('C:\Autonomie practice\cycle.xls','Input_data');
nrows = size(sch_cycle,1);

Answer 1

[Jonathan Sullivan]

sch_cycle=xlsread('C:\Autonomie practice\cycle.xls','Input_data');
nrows = size(sch_cycle,1)-1;

Answer 2

[Dr. Seis]

If you mean you want to set "sch_cycle" to have nrows - 1, then no need to actually determine "nrows" beforehand (just use "end"):

sch_cycle = sch_cycle(1:end-1,:);

You can setup an "if" statement in order to make sure "nrows" is greater than 1.

[Sean de Wolski]

or you could use max:

sch_cycle(max(1,size(sch_cycle,1)-1),:)

[Dr. Seis]

Looks like "end" will still work there, too:

sch_cycle(1:max(1,end-1),:); % For all rows except last row

sch_cycle(max(1,end-1),:); % For just second to last row

[John]

Thanks for all the suggestions guys.