Array function for ranges

조회 수: 2 (최근 30일)
Azura Hashim
Azura Hashim 2017년 2월 7일
편집: Jan 2017년 2월 15일
Hi,
I have a binary image in a matrix, call it binarymage. I then want to determine whether various areas in the image are white pixels only. The boundaries for the areas of interest are defined in as follows:
left=[1]; right=[11]; top=[5,6,7,8]; bottom=[15,16,17,18];
So in this example I have 4 boxes. How can get a result that tells me which boxes are white only. Example: whiteboxes=[1,0,1,0].
I think I need arrayfun but have not been successful after several attempts. Appreciate any help please. Thank you.

채택된 답변

Saurabh Gupta
Saurabh Gupta 2017년 2월 15일
You should be able to do it using a combination of not and any commands. One example could be as follows.
tempBox = binarymage(top(1):bottom(1), left(1):right(1));
whiteboxes(1) = not(any(tempBox(:)));

추가 답변 (1개)

Jan
Jan 2017년 2월 15일
편집: Jan 2017년 2월 15일
A simple loop is a good point to start from:
left = 1;
right = 11;
top = [5,6,7,8];
bottom = [15,16,17,18];
whiteboxes = false(1, 4);
for k = 1:4
whiteboxes(k) = all(binarymage(left:right, top(k):bottom(k)));
end
What exactly is a "white" pixel? Does it have the value 1 or 0? Here I assume, that white mean 1. If 0 is meant, replace all() by ~any().

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