Hi again,
I have a really large excel file which I have imported in Matlab.
So it's a large array with dimensions : 588845x10 double
how can I get the average value from the first 48 values, then the average from the the next 48 values and so on?
many thanks,
Nikolas

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Guillaume
Guillaume 2017년 1월 30일
편집: Guillaume 2017년 1월 30일

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>>588845/48
ans =
12267.604
The number of rows is not divisible by 48. What are you planning to do with the last few rows?
Assuming you have a number of rows divisible by 48, the easiest is to reshape the matrix into 48 rows, and take the mean along the rows.
m = reshape(1:5888450, 588845, 10); %demo data, replace by your own matrix
croppedm = m(1 : size(m,1)-mod(size(m, 1), 48), :); %crop number of rows to multiple of 48
meancroppedm = squeeze(mean(reshape(croppedm, 48, [], size(m, 2)), 1)) %mean along rows
The mean of the last portion:
meancutm = mean(m(size(m, 1)-mod(size(m, 1),48) : end, :), 1)
The two combined
mean48 = [meancroppedm; meancutm]

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