I have a polar plot. Is there a way to label the axes?
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For the r axis, I would like to label "Energy (eV)" How do I do that?
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Walter Roberson
2017년 1월 9일
편집: Walter Roberson
2017년 1월 9일
Oddly, the new polarplot() that creates Polar Axes objects, has no provision for axes labels.
I just now put in an enhancement request for this.
답변 (3개)
Steven Lord
2017년 1월 9일
In release R2016a or later if you create a polaraxes, either using that function directly or by creating a polarplot, you can get the RAxis property of that polaraxes. The RAxis object has a property named Label that contains a text object, and that text object has a property named String.
ax = polaraxes;
rule = ax.RAxis;
rlabel = rule.Label;
rlabel.String = 'hello world';
You can chain together the property references if you want to make this a two line code:
ax = polaraxes;
ax.RAxis.Label.String = 'dlrow olleh';
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Steven Lord
2017년 1월 11일
Try running this. I had to generate some simple a and f data, but it should show the general technique.
a = sort(pi*rand(1, 100));
f = sin(a);
polarplot(a, f, '-ob')
ax = gca;
rruler = ax.RAxis;
rruler.Label.String = 'Energy (eV)';
The rruler.Label object has properties Interpreter and Rotation, among others, so you can customize it even more than simply changing the String.
Walter Roberson
2017년 1월 9일
polar() is pretty much plot() of pol2cart() behind the scenes. There is no support for r or theta labels. There is the xlabel and ylabel from the underlying axes, but that is not very useful.
So, what you have to do is pick out an axes position in r and theta terms, pol2cart those into x y components, and text() at that position.
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Star Strider
2017년 1월 9일
If you have R2016a or later, use the polarplot function. It gives you the option of specifying the 'RTickLabel' (link) values. That is likely as close as you can get to what you want to do.
You will need to use sprintf and strsplit to create the labels and a cell array to use as the radius labels.
Example:
eV = linspace(0, 10, 5);
eVstr = sprintf('%.1f eV\n', eV);
eVlbl = strsplit(eVstr, '\n');
eVlbl = eVlbl(1:end-1);
The last element of the original ‘eVlbl’ is an empty string that can cause problems with vector length matching, so it is necessary to eliminate it by the second ‘eVlbl’ assignment.
Experiment with it. If you have problems, describe them here. We can help.
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Star Strider
2017년 1월 11일
I was specifically suggesting the arguments to your polarplot calls. Do we need those to understand your problem, or will any vectors do for ‘a’, ‘f’ and the rest?
Walter Roberson
2017년 1월 12일
The example Steven http://www.mathworks.com/matlabcentral/answers/319725-i-have-a-polar-plot-is-there-a-way-to-label-the-axes#comment_419725 gave works for me. I would not say that the location or direction it chooses is exactly my first choice. You might want to set the ruler Rotation to 0 or change the font size or something like that.
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