필터 지우기
필터 지우기

Sliced Variables in "parfor"

조회 수: 1 (최근 30일)
Reza Teimoori
Reza Teimoori 2016년 12월 31일
댓글: Matt J 2016년 12월 31일
I'd like to run a loop using parfor similar to this:
A = zeros(10,10,10,10);
parfor i = 1:100
ind = ceil(rand(1,4)*10);
A(ind) = A(ind) + 1;
end
This yields to an error due to the way indices of A is being defined in each iteration. I understand that one workaround can be to save the "ind" values in each iteration in a temporary variable and use them in a later regular loop to update the matrix A. But I was wondering if there is any way that lets me do the whole thing in a single parfor loop. In my case the matrices and indices that I'll be working with are so large that I can't save them for use in a later loop.
Thank you all!
  댓글 수: 1
Matt J
Matt J 2016년 12월 31일
Are you sure you didn't really mean as follows?
parfor i = 1:100
ind = ceil(rand(1,4)*10);
i=ind(1);
j=ind(2);
k=ind(3);
l=ind(4);
A(i,j,k,l) = A(i,j,k,l) + 1;
end

댓글을 달려면 로그인하십시오.

답변 (1개)

Matt J
Matt J 2016년 12월 31일
Suppose you wanted to do this 5 million times:
A = zeros(10,10,10,10);
M=5;
N=1e6;
parfor i = 1:M
subs = ceil(rand(N,4)*10);
A=A+accumarray(subs,1,size(A));
end
Obviously there are different possible choices of partitioning parameters M,N. You want to make N as large as your RAM reasonably allows because that will use the most vectorization.

카테고리

Help CenterFile Exchange에서 Matrices and Arrays에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by