Error using histc. First Input must be a real non-sparse numeric array.

data = load('Day10.mat');
data = data.timestamps;
data{1} = data{1,1}';
data{2} = data{1,2}';
data{3} = data{1,3}';
data{4} = data{1,4}';
data{5} = data{1,5}';
data{6} = data{1,6}';
data{7} = data{1,7}';
data{8} = data{1,8}';
edges = [0 33.3115 33.3125 33.3135 33.3145 33.3155 33.3165 33.3175 33.3185 Inf];
n = histc(data, edges);
bar(n, 'histc');
set(gca,'XTick',1:length(edges),'XTickLabel', {edges(1:10)});
legend('cam1','cam2','cam3','cam4','cam5','cam6','cam7','cam8');
legend('show');
xlabel('Time(ms.)');
ylabel('Count');

The above shown script is what I am using to generate histogram which should look something like this:

But I am not able to do it. Can anyone suggest me how to go about do this? The data is stored in this format:

The timestamps variable is 1*8 cell with each cell containing 1*213549 double values.

Answer 1

[Walter Roberson]

temp = cellfun@(X) reshape(histc(X, edges), [], 1), data, 'Uniform', 0);
n = horzcat(temp{:});

Answer 2

[dpb]

Use cell2mat to "smoosh" the cell arrays into one array before histc

If have later release, there's a newer histogram function that just might be cell array literate, not sure, but worth checking, perhaps...

[Walter Roberson]

That would not get you the separate bars.

[dpb]

Should if they're arranged by columns unless I mistook the query I think Walter???

[Walter Roberson]

Ah, you are right, cell2mat could turn that into an array whose columns histc() would operate over. That is a better solution than what I did.

[dpb]

Whew! :) Thought it was ok when posted it... vbg

Does the newer histogram function work more better here than " histc classic"?