Creatig a matrix from variables in workspace

조회 수: 36 (최근 30일)
Dimitris Pasias
Dimitris Pasias 2016년 12월 23일
답변: Addy 2018년 10월 29일
I have 80 workspace variables of size 1 x 3649. The variables are named t001 t005 t010 t015 t020 t025...etc until t195. I want matlab to read them from workspace and put them all together in a matrix to create a matrix 80 x 3649. Please advise me how to do it.Thnanks!

답변 (3개)

Massimo Zanetti
Massimo Zanetti 2016년 12월 23일
편집: Massimo Zanetti 2016년 12월 23일
How did you get these variables?
It is not good practice to handle workspace variables after their definition. Better saving all these vectors t0xx (at the moment they are created) in a cell array C of size 80-by-1 and then build a matrix with cell2mat(C).
  댓글 수: 2
Dimitris Pasias
Dimitris Pasias 2016년 12월 24일
편집: Dimitris Pasias 2016년 12월 24일
i got them using strcat and load commands
clear all;
clc;
cd('C:\Users\User\Desktop\imagephd');
for k = 1:4:7;
C = strcat('roipb00',num2str(k),'.jvc');
load(C);
end
for k = 10:5:99;
C = strcat('roipb0',num2str(k),'.jvc');
load(C);
end
for k = 100:5:400;
C = strcat('roipb',num2str(k),'.jvc');
load(C);
end
for cv = who('roipb*')'; %transpose to get a row cell array
eval(sprintf('U%1$s = 0.65.*sqrt((%1$s(:,3).^2)(%1$s(:,4).^2))',cv{1})); %1$s is replaced by var name, output is named meanvarname
end
for cvn = who('Uroipb*')'; %transpose to get a row cell array
eval(sprintf('t%1$s =transpose(%1$s)', cvn{1})); %1$s is replaced by var name, output is named meanvarname
end
I want the workspace variables from the last eval to a single matrix 80 x 3649
Thanks
Massimo Zanetti
Massimo Zanetti 2016년 12월 27일
Dimitris, avoid using eval.
If you cannot manage to save your variables in a different way (don't save variables with numbered names!!!) such as in a structure or cell, then please consider Stephen Cobeldick answer.

댓글을 달려면 로그인하십시오.


Stephen23
Stephen23 2016년 12월 24일
편집: Stephen23 2016년 12월 24일
The best solution is to never use numbered variables.
As everyone with experience will tell you, avoid using eval. The trick is to load into a variable (which is a structure):
S = load(C);
Once you have the structure you can identify its fieldnames and do whatever you want with the field data. This will be faster and much less buggy than using evil eval. You would probably do something a bit like this outline (pseudocode):
vec = dir(fullfile(pathname,filestring));
out = ... preallocate a matrix of the right size.
for k = 1:numel(vec)
str = fullfile(pathname,vec(k).name);
tmp = load(str);
fld = fieldnames(tmp);
dat = getfield(tmp,fld{1}); % pick the correct field
out(k,...) = dat;
end
If you have never used the functions in my code then read the documentation for each function carefully, try them out, and you will learn some new functions and how to write better code. That will make it worthwhile!
Also note that you should avoid using cd. Using cd is slow, unnecessary, and makes debugging harder. Just pass the full file path instead, as my code shows.

Addy
Addy 2018년 10월 29일
Hi,
I have got the same kind of problem and "Stephen Cobeldick's" answer helped me. "getfield" function did the trick. I had different matrices with each 4 columns with names and I wanted to arrange them in a single matrix to be able to use that as the input vector for ANN.
So this helped me to achieve the result.
I have cleared all the variables except of what I need and saved them in a mat file.
x1=load('featurevector.mat');
x2(:,1)=fieldnames(x1);
feature_vector=[];
for i=1:size(x2,1)
feature_vector=vertcat(feature_vector,getfield(x1,x2{i}));
end
I hope this helps.

카테고리

Help CenterFile Exchange에서 Whos에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by