Struct data assignment has error

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shawin
shawin 2016년 12월 16일
댓글: Adam 2016년 12월 16일
am trying to calculate a distance for struct data type. The distance method is:
function ssd=distances(x, c)
m=size(x,1);
ssd = zeros(m, k);
k=size(c,1);
for i= 1:k
z = bsxfun(@minus,x, c(i,:));
ssd(:, i) = sqrt(sum(z.^2, 2));
end
end
I have c which is a random number produced from the formula below:
for i=1:20
pop(i).Position=unifrnd(2,2,4);
pop(i).dist=distances(data,pop(i).Position);
end
I have c which is a random number produced from the formula below:
for i=1:20
pop(i).Position=unifrnd(2,2,4);
pop(i).dist=distances(data,pop(i).Position);
end
x=data is 100x2.
The issue is when I call the distance method it does not accept the passing argument. pop(i).dist=distances(data,pop(i).Position);
the error is :
Non-singleton dimensions of the two input arrays must match each other. Error in distances (line 8) z = bsxfun(@minus,x, c(i,:));
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shawin
shawin 2016년 12월 16일
편집: shawin 2016년 12월 16일
@Adam,the data is 2 Dimension and it is fixed. now we have c : is 1x4 and the only option that i have is convert 1x4 to 2x2 because this is the nature of the algorithm , my issue is how can i produce the pop(i).position= 2x2 ? instead of 1x4.
i have put the error : Non-singleton dimensions of the two input arrays must match each other. Error in distances (line 8) z = bsxfun(@minus,x, c(i,:));
Adam
Adam 2016년 12월 16일
pop(i).Position= reshape( unifrnd(2,2,4), [2 2] );

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답변 (1개)

KSSV
KSSV 2016년 12월 16일
편집: KSSV 2016년 12월 16일
Try
pop(i).dist=distances(data,pop(i).Position);
Instead of
pop(i).dist=distances(x= data,pop(i).Position=c);
Also in the function, distances copy initilaize ssd after getting k. What does this mean?
ssd(:,i) = sqrt(z.^2,2);
sqrt takes only one input. sqrt(z.^2); But it has no meaning, in squaring and finding the square root. Chekc the initilaization of ssd, it will throw error.
  댓글 수: 2
shawin
shawin 2016년 12월 16일
편집: shawin 2016년 12월 16일
@ KSSV Yes , I just put (x= data,pop(i).Position=c) for explanation. sorry ssd is : ssd(:, i) = sqrt(sum(z.^2, 2));
KSSV
KSSV 2016년 12월 16일
Consider the other comments....you have to change your function distances

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