please any one can understand me this and I want to display any word and here frq like city 3 .gg.txt contain this text I live in a city called hilla this city located in.the center of iraq it is not too large.hilla contain many resturants in her

 stp_w={ 'I', 'called',' this' ,'in', 'the',' of', 'it', 'is', 'not' ,'too' ,'many' ,'here', 'these', 'one', 'and', 'that',};
 f = fopen('gg.txt','r');
 I = textscan(f,'%s',100);
 d=I{1};
 for i=1:length(d)
 x = strmatch(d(i), stp_w);
c=0;
 if x~=1
  for j=1:length(d)
      x = strmatch(d(i),d(j) );
      if x==1
          c=c+1;
      end
  end
 feq(i)=c;  
end
 end

Answer 1

[KSSV]

clc; clear all ;

stp_w={ 'I', 'called',' this' ,'in', 'the',' of', 'it', 'is', 'not' ,'too' ,'many' ,'here', 'these', 'one', 'and', 'that',};
f = fopen('gg.txt','r');  % opens text file gg.txt
I = textscan(f,'%s',100); % scans the data into strings in I
d=I{1};    % the first line
for i=1:length(d)   % loop for every data in first line 
    x = strmatch(d(i), stp_w);    % matching each string in d with stp_w
    c=0;     % a constant c = 0, for count 
    if x~=1  % if string is not matching 
        for j=1:length(d) % loop for every data in first line 
            x = strmatch(d(i),d(j) );  % comapring the strings in text file with it selfs
            if x==1     % is string matches 
                c=c+1;  % count increased 
            end   
        end
        feq(i)=c;     % saving ht ecount 
    end
end

[hiba rashed]

thanks a lot and how can I find the frequency of each answer like this ex? ex/ city 3 Hilla 2 these words in gg.txt