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Calculate t maximums in single vector

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Moe Joe
Moe Joe 2016년 12월 3일
편집: Stephen23 2016년 12월 3일
I have an iterative program for linear block codes (k,n), and at some point, I add code-words base10
The addition result in a vector of size (1,n)
I need to find the maximum (t) elements in this vector without going into loops operations, as the time of program execution is very important.
Example: if my Vector is (V)=(1,n)
V=[68 61 35 37 18 80 50 36 78 24 85 82 85 38 39 87 47 58 70 97 55 64 58 93 87 17 18 25 76 20 99 71]
I want a direct command that can calculate the maximum 5 elements of the Vector (V).
Kindly help.

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Star Strider
Star Strider 2016년 12월 3일
You can always create your won function file from this code to produce your ‘direct command’:
V=[68 61 35 37 18 80 50 36 78 24 85 82 85 38 39 87 47 58 70 97 55 64 58 93 87 17 18 25 76 20 99 71];
Vs = sort(V,'descend');
Out = Vs(1:5)
Out =
99 97 93 87 87
  댓글 수: 4
Moe Joe
Moe Joe 2016년 12월 3일
Perfect, thanks a lot.
Star Strider
Star Strider 2016년 12월 3일
My apologies for the delay. The other option would be to ask for two outputs from the sort function. The second will give you the indices of the sorted elements in the original vector.
From the documentation:
  • [B,I] = sort(_) also returns a collection of index vectors for any of the previous syntaxes. I is the same size as A and describes the arrangement of the elements of A into B along the sorted dimension. For example, if A is a numeric vector, B = A(I).

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추가 답변 (1개)

John D'Errico
John D'Errico 2016년 12월 3일
Sort them. Then take the first 5 elements from the sort. WTP?
No. It is not ONE single command. Not an option. Of course, nothing stops you from writing a function that does exactly that, in which case it will be one line.
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Moe Joe
Moe Joe 2016년 12월 3일
편집: Stephen23 2016년 12월 3일
Already did this function:
% This is a function locates the positions of maximum (t) numbers in a
function [v]=maxvic(X,t);
vector V(1,n).
n=length(X);
v=zeros(1,n);
for i = 1:t;
[y j]=max(X,[],2);
v(j)=1;
X(j)=0;
end
end
But thought the more expert than I could advice a better solution.

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