Divide a cell arrays with a part of another cell array

Hi everyone,

I want to divide a cell array A, 2x100 with the last 100 elements of another cell array B 1x101.All of the elements of both cell arrays are scalars. I have tried

c=num2cell(cell2mat(A)./cell2mat(B{1,2:end}));

but it doesn't work. Thanks in advance.

Answer 1

[James Tursa]

Try this:

C = num2cell(bsxfun(@rdivide,cell2mat(A),cell2mat(B(1,2:end))));

Note that B{1,2:end} using the curly braces will be a comma-separated-list of the contents of B, whereas B(1,2:end) using parentheses will simply be another cell array.

Answer 2

[Walter Roberson]

c = num2cell( cell2mat(A) ./ repmat( cell2mat(B(1,2:end)), size(A,1), 1) );

If you are using R2016b or later you can

c = num2cell( cell2mat(A) ./ cell2mat(B(1,2:end)) );

which is the same as what you had except it uses B(1,2:end) rather than B{1,2:end}