Indexing into a multidemesional array using a multidimensional array

조회 수: 5 (최근 30일)
Kevin McAughey
Kevin McAughey 2016년 11월 18일
댓글: Guillaume 2016년 11월 18일
This question seems similar to a previously answered question, but I'm not sure if the answer there applies to my problem.
I have an array, X, which has dimensions k by m by n and I have another array, Y, with indices for the first dimension k, which has dimensions m by n. I want to create an output matrix of m by n of each value of X in the k dimension where the index in that k dimension corresponds to the value in Y for each value of m and n.
I know that is a bit confusing, but in essence I want to achieve the following code via clever application of indexing, rather than using nested for loops.
m = size(X,2);
n = size(X,3);
for m_count = 1:length(m)
for n_count = 1:length(n)
output(m_count,n_count) = X(Y(m_count,n_count),m_count,n_count)
end
end

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Guillaume
Guillaume 2016년 11월 18일
I think it should rather be:
[rows, columns] = ndgrid(1:size(Y, 1), 1:size(Y, 2));
output = X(sub2ind(size(X), Y, rows, columns))
  댓글 수: 2
Kevin McAughey
Kevin McAughey 2016년 11월 18일
This seems to work perfectly, now I'll just have to look through it so that I can understand why!
Guillaume
Guillaume 2016년 11월 18일
rows and columns are just two matrices corresponding to the row and column indices of the corresponding elements of Y.
sub2ind converts these three coordinate matrices into a single linear index which can be used to index X.

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추가 답변 (1개)

Jan
Jan 2016년 11월 18일
편집: Jan 2016년 11월 18일
Try this:
output = X(sub2ind(size(X), Y(:), 1:size(x,2), 1:size(x,3))
  댓글 수: 1
Kevin McAughey
Kevin McAughey 2016년 11월 18일
When I tried this it threw the following error:
Error using sub2ind (line 51)
The subscript vectors must all be of the same size.

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