Problem in plotting the matrix over an image.
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I am required to read an image,find out its rgb channels and then in those channels separately,mark the pixels whose value exceeds above a certain threshold value.I wrote the following code for marking the pixels but they are not getting marked and I am getting the error that it exceeds matrix dimensions.What am I doing wrong in the code? Below is the code-
img=imread('test.jpg');
imshow(img)
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
[r,c,~]=size(img);
indx=zeros(r,c);
for i=1:r
for j=1:c
if ((redchannel(i,j))>=180)
indx(i,j)=1;
end
end
end
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
hold off
end
end
댓글 수: 5
KSSV
2016년 11월 16일
Your code is taking hell lot of time: Use below modified code.
img=imread('Prachi Sharma image');
imshow(img)
%
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
%
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
%
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
%
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
%
[r,c,~]=size(img);
indx=zeros(r,c);
indx(redchannel>=180) = 1 ;
% for i=1:r
% for j=1:c
% if ((redchannel(i,j))>=180)
% indx(i,j)=1;
% end
% end
% end
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
drawnow
hold off
end
end
Can you tell me what you are trying to do here? Why loop needed here?
for i=1:r
for j=1:c
imshow(r1)
hold on
plot(indx(:,1),indx(:,2),'b*');
drawnow
hold off
end
end
Prachi Sharma
2016년 11월 16일
Important note:
redchannel = img(:,:,1);
rs = zeros(size(redchannel));
r1 = cat(3, redchannel, rs, rs);
That's very dangerous because there's no class specified in the zeros call. rs is always going to be of class double, whereas redchannel may be of a different class (if it comes from a jpeg image, it'll be uint8). You're then combining matrices of different classes which may not produce the result you expect.
Much safer would be:
redchannel = img(:,:,1);
rs = zeros(size(redchannel), class(redchannel)); %make sure rs is of the same class as redchannel
r1 = cat(3, redchannel, rs, rs);
or even better:
r1 = img; %r1 is same class as img
r1(:, :, [2 3]) = 0; %note that the double 0 gets converted to 0 of the class of r1
Image Analyst
2016년 11월 16일
Do you want to change the actual pixel values, like make them red or something? OR do you want to leave the pixel values the same and just change how they are displayed, like use a colormap where those pixels are red, or use a binary overlay ?
Prachi Sharma
2016년 11월 17일
답변 (3개)
KSSV
2016년 11월 16일
clc; clear all ;
img=imread('Prachi Sharma image');
imshow(img)
%
redchannel=img(:,:,1);
greenchannel=img(:,:,2);
bluechannel=img(:,:,3);
%
rs=zeros(size(redchannel));
r1=cat(3,redchannel,rs,rs);
figure
imshow(r1)
%
gs=zeros(size(greenchannel));
g1=cat(3,gs,greenchannel,gs);
figure
imshow(g1)
%
bs=zeros(size(bluechannel));
b1=cat(3,bs,bs,bluechannel);
figure
imshow(b1)
%
[r,c,~]=size(img);
indx=NaN(r,c);
indx(redchannel>=180) = 1 ;
%
imshow(r1) ;
x = 1:c ;
y = 1:r ;
[X,Y] = meshgrid(x,y) ;
hold on
plot3(X,Y,indx,'*b') ;
댓글 수: 3
Prachi Sharma
2016년 11월 16일
편집: Prachi Sharma
2016년 11월 16일
KSSV
2016년 11월 16일
You try it out...this is the way the matrix size of x,y making equal to indx. Do consider the Guillaume comments.
Prachi Sharma
2016년 11월 16일
find will return the locations of all the values above the threshold, there's no need for a loop
img = imread('test.jpg');
redchannel = img(:, :, 1);
[row, column] = find(redchannel > 180); %no need for loop
redimage = img; redimage(:, :, [2 3]) = 0;
figure;
imshow(redimage);
hold on;
plot(column, row, 'b*'); %column, row <=> x, y. Stupid matlab can't decide on a single coordinate system!
and do the same for green and blue.
edit: also see my comment to the question about using zeros with no class specified.
댓글 수: 11
Prachi Sharma
2016년 11월 16일
편집: Prachi Sharma
2016년 11월 16일
Guillaume
2016년 11월 16일
redimage(:, :, [2 3]) selects all the rows, all the columns and only index 2 and 3 of the third dimension. index 2 is the green channel, and index 3 is the blue channel. In effect, this set all the green and blue value to 0. If you wanted to keep just the green channel, then:
img(:, :, [1 3]) = 0; %1and 3 is red and blue respectively
find use the normal matlab convention where the first value it returns is the row of the matrix, and the second value is the column of the matrix. plot and a few other functions (most of of the image processing toolbox, as well as gradient, meshgrid and maybe more) use a different coordinate system (x, y) where x corresponds to the columns, and y to the rows. This is matches the way you normally references coordinates outside matlab but as a result you end up with two different coordinates system where one is swapped compared to the other.
Personally, I think it's stupid (hence my comment in the code). In my opinion it would be much better to be internally consistent but that's what it is: plot uses (x, y) coordinates which is (column, row), find uses (row, column) which is (y, x).
Image Analyst
2016년 11월 16일
MATLAB is not the only one. Have you ever noticed the two conventions for numeric keypads - how your keyboard and phone are upside down with respect to each other? But yes, x,y and row,column trips up lots of people.
Prachi Sharma
2016년 11월 17일
Prachi Sharma
2016년 11월 17일
No, it doesn't and it can't. The code I've written does exactly and only this:
- find the locations of pixels whose red pixels are above the threshold
- creates a duplicate of the image where only the red channel is active
- displays the image
- overlays on the display blue stars at the locations found in the 1st step.
At no point does it alter the value of pixels above any threshold.
Prachi Sharma
2016년 11월 17일
KSSV
2016년 11월 17일
As suggested by Guillaume in other discussion.
[Y,X,V] = redchannel>=180 ;
Follow the same for other channels.
Prachi Sharma
2016년 11월 17일
KSSV
2016년 11월 17일
Dear friend then type it..what is stopping you?
Prachi Sharma
2016년 11월 17일
편집: Prachi Sharma
2016년 11월 17일
Image Analyst
2016년 11월 17일
Try something like this:
% Extract the individual red, green, and blue color channels.
redChannel = rgbImage(:, :, 1);
greenChannel = rgbImage(:, :, 2);
blueChannel = rgbImage(:, :, 3);
% Make mask where ANY of the color channels is saturated.
saturatedPixels = redChannel == 255 | greenChannel == 255 | blueChannel == 255;
% Make red channel 255, and other color channels 0 where there is saturation
redChannel(saturatedPixels) = 255;
greenChannel(saturatedPixels) = 0;
blueChannel(saturatedPixels) = 0;
% Recombine separate color channels into a single, true color RGB image.
rgbImage = cat(3, redChannel, greenChannel, blueChannel);
imshow(rgbImage);
Now your RGB image will be pure red wherever ANY pixel of ANY color channel is saturated (value of 255). For an image in the range 0-1, use 1 instead of 255. For a uint16 image, use 65535 instead of 255.
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