bsxfun with AND condition

How can I use a code to see if compare1<q{x,y}<compare2

Basically the lt/gt function combined with an and function?

bsxfun(@lt,q{x,y},compare2 & q{x,y},compare1);

Answer 1

[James Tursa]

Assuming q{x,y} and compare# are different sizes and need bsxfun, just & the two separate calculations:

result = bsxfun(@lt,compare1,q{x,y}) & bsxfun(@lt,q{x,y},compare2);

For R2016b you would not need bsxfun for this at all but could code the < operations directly.

Answer 2

[AA]

no it doesnt work. it gives me one set that is less than compare 2 and another set that is less than compare 1. after that it combines these two sets.

I need compare1<q{x,y}<compare2

[James Tursa]

Please post your code so we know what "... doesn't work ..." means to you.