Problem in if-else if-else structure
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Hi, I have written the following program. But it does not output the result I get from manual calculations. Perhaps I have gone wrong in writing the logic. The program is as below.
if X1(i)==a(i) && X2(i)==b(i)
t(i)= a(i)* b(i);
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==a(i+1) && X2(i+1)==NaN
t(i)= a(i)* a(i+1);
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==NaN && X2(i+1)==b(i+1)
t(i)= a(i)* b(i+1);
else if X1(i)==NaN && X2(i)== b(i)&& X1(i+1)==a(i+1) && X2(i+1)==NaN
t(i)= b(i)* a(i+1);
else if X1(i)==NaN && X2(i)== b(i)&& X1(i+1)==NaN && X2(i+1)==b(i+1)
t(i)= b(i)* b(i+1);
else
t(i)= 0;
end
end
end
end
end
The input is as below. X1=NaN a(2) NaN a(4) a(5) NaN NaN
X2= NaN b(2) b(3) NaN b(5) NaN NaN
i=1:7 and i=8 equals to i=1
The output is as below.
t= 0 c 0 0 d 0 0
But there should be output at t(3) and t(4). Can anybody point out where I went wrong? Thanks
답변 (1개)
James Tursa
2016년 11월 11일
편집: James Tursa
2016년 11월 11일
You can't compare to NaN with the == operator, since NaN is not equal to anything (including itself). You must use the isnan function. E.g.,
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==a(i+1) && X2(i+1)==NaN
should be
else if X1(i)== a(i) && isnan(X2(i)) && X1(i+1)==a(i+1) && isnan(X2(i+1))
etc.
For example,
>> a = nan
a =
NaN
>> a == nan
ans =
0
>> a == a
ans =
0
댓글 수: 6
Walter Roberson
2016년 11월 11일
What error message are you seeing?
KalMandy
2016년 11월 11일
James Tursa
2016년 11월 11일
Please show the exact code you are using to build X1 and X2.
KalMandy
2016년 11월 11일
KalMandy
2016년 11월 11일
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