Index exceeds matrix dimensions.

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Aldo
Aldo 2016년 11월 4일
답변: Alexandra Harkai 2016년 11월 4일
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
n=25; h=2.5/n; t=h*(0:n); f=f21(t).^2; T26=pi*h*(sum(f)-(f(1)+f(n+1))/2);
n=52; h=2.5/n; t=h*(0:n); f=f21(t).^2; T52=pi*h*(sum(f)-(f(1)+f(n+1))/2);
Can't figure why Index is exceeding the matrix dimensions. Since the graph goes up to 5.

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Alexandra Harkai
Alexandra Harkai 2016년 11월 4일
Did you check what you get for f?
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
This returns a scalar, so f will be of size 1*1. If you want element-wise division, then this will not fail:
f21=@(x)(exp(-x/3))./(4-cos(pi*x));

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