Secant method error, "subscript indicies must be real or positive integers"

조회 수: 2 (최근 30일)
Harjot Purewal
Harjot Purewal 2016년 10월 31일
댓글: Harjot Purewal 2016년 10월 31일
here is my code, I get the error at line 10 at x(n+1) = x(n) - .... I have also attached it as an .m file
Matlab code
y = @(x) x.^3 - .3;
x(1) = .01;
x(2) = .02;
tol = 1e-5;
eps = 500;
iteration_secant = 0;
n = 1;
while abs(eps) > tol
x(n+1) = x(n) - ((y(x(n))*(x(n)-x(n-1))/(y(x(n))-y(x(n-1)))));
iteration_secant = iteration_secant +1;
eps = ((x(n+1) - x(n))/x(n));
n=n+1;
if n > 100
break
end
end
x(n+1)

답변 (1개)

Roger Stafford
Roger Stafford 2016년 10월 31일
You enter the while loop with n = 1. This means that x(n-1) would have an index value of zero. This is a no-no in Matlab. You will have to revise your code to avoid this.
  댓글 수: 1
Harjot Purewal
Harjot Purewal 2016년 10월 31일
I have changed it to n=2; from n=1; however I still get the same error and for some reason the value of n is still 1 when I run my code any idea of why this is the case?

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Entering Commands에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by