Finding intersection point of the lines
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Hi I have data sets for two lines. i.e. x1,y1 and x2,y2. So i can plot the lines using these point data sets. I would like to know the point (x,y)where these lines intersect each other. Please note that i have tried both [x,y]=intersections(x1,y1,x2,y2); and [x,y]=curveintersect(x1,y1,x2,y2);
i would appreciate if you can tell me the exact command for this purpose.
Regards
댓글 수: 1
Jorge Celedón
2018년 12월 13일
편집: madhan ravi
2018년 12월 13일
채택된 답변
추가 답변 (4개)
Jorge Celedón
2018년 12월 13일
편집: madhan ravi
2018년 12월 13일
1 개 추천
댓글 수: 2
Nicholas Ayres
2022년 1월 26일
Heads up to people who find this. This requires the Mapping Toolbox
Vladimir Jara
2022년 9월 23일
thanks for the heds up!
Andrei Bobrov
2012년 3월 5일
data = rand(20,3);
x1 = sort(data(:,2));
x2 = sort(data(:,3));
y = data(:,1);
pp = interp1(x1,y,'linear','pp');
pp2 = interp1(x2,y,'linear','pp');
xx = xx(max(x1(1),x2(1)) <= xx & min(x1(end),x2(end)) >= xx);
func = @(x)ppval(pp,x)-ppval(pp2,x);
xb = xx([true; diff(func(xx) > 0) ~= 0]);
i1 = hankel(1:2,2:numel(xb));
xout = arrayfun(@(z)fzero(func, xb(i1(:,z))), (1:size(i1,2))' )
댓글 수: 1
Agnieszka Dybalska
2021년 1월 6일
It returns - not known function xx...
mohammed wasiullah
2017년 4월 5일
0 개 추천
how to find the intersection between the curve and the straight ?
댓글 수: 1
Tan Kah Loon
2017년 4월 18일
Example,y1=x^2+2x+3,y2=2x^2+3x+4 , you have to combine two eq and you get ((x^2+X+1)), type f=[1 1 1] to get the polynomials func and roots (f) for its roots.Next, you have to type your 1st equation into p=[1 2 3], after that, pvals=polyval (p,-0.5) and you will find the 1st intersection. The 2nd intersection use back the same method to find.
Preetham Manjunatha
2022년 2월 8일
0 개 추천
Here is the link to find the intersection point of two line segments/lines. A fast two line intersection point finder based on the line parametric space. Finds the intersection point between two lines if it exists or else submits NaN.
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