convert vector into 'matrix equivalent'

I have a vector of binomially distributed random numbers from i = 0 to n eg R = [0 1 2 1 4]'
I want to convert this this into a matrix of dimensions length( R ) by n where each row contains either zeros or ones. The number of ones required in each row is taken from the equivalent value in R. Otherwise values are zero. I would like the position of the ones within each row to be random. For instance, if R above and n = 5 then one matrix would be S = [ 0 0 0 0 0; 0 0 1 0 0; 0 1 1 0 0; 0 0 1 0 0; 1 1 1 0 1]
In practice,R is large with 1e6 values so I need the operation to be as fast as possible.
Many thanks!

댓글 수: 1

Matt J
Matt J 2016년 10월 9일
In practice,R is large with 1e6 values
If m=length( R ) what are the typical magnitudes of both m and n?

댓글을 달려면 로그인하십시오.

 채택된 답변

Walter Roberson
Walter Roberson 2016년 10월 9일

1 개 추천

[~, permidx] = sort( rand(length(R), n), 2);
S = permidx <= repmat(R(:),1,n);

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Random Number Generation에 대해 자세히 알아보기

질문:

J T
2016년 10월 9일

댓글:

J T
2016년 10월 9일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by