Find match for a pair of rows in cell arrays
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I have 2 cell arrays of equal length, e.g.
>> alfa = {'a'; 'b'; 'c'; 'b'; 'a'; 'c'}
alfa =
'a'
'b'
'c'
'b'
'a'
'c'
>> beta = {'b'; 'd'; 'a'; 'd'; 'a'; 'a'}
beta =
'b'
'd'
'a'
'd'
'a'
'a'
and I want to find where the pairs are repeated, which pair is it and the index where the repeated pairs are located.
So, in this case the index 2 and 4 correspond to the repeated pair 'b' and 'd', and the index 3 and 6 correspond to the repeated pair 'c' and 'a'. It is important that I know which pair is it and all the indexes where this pair is repeated.
Thank you.
댓글 수: 1
Adam
2016년 9월 29일
What is the significance of having two cell arrays? I don't see what the relevance of the 2nd one is other than just as another example. Is it supposed to be used in some way?
채택된 답변
dpb
2016년 9월 29일
편집: dpb
2016년 9월 29일
Adam's on the right track, just didn't quite recognize the problem description--
>> ab=[char(alfa) char(beta)]; % mush the two arrays together
>> [u,ia,ib]=unique(ab,'rows'); % get the combinations that are extant
>> u(histc(ib,unique(ib))>1,:) % find the ones with more than one occurrence
ans =
bd
ca
>>
The alternate returns from histc and unique will provide the positions.
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추가 답변 (1개)
Adam
2016년 9월 29일
편집: Adam
2016년 9월 29일
[C, ia, ic] = unique( alfa );
should give you this information. The C vector gives the characters and the ic vector tells you where they occur so repeated indices show the locations of the same letter.
[C, ia, ic] = unique( alfa )
C =
'a'
'b'
'c'
ia =
1
2
3
ic =
1
2
3
2
1
3
댓글 수: 3
dpb
2016년 9월 29일
He stated he had two cell arrays only you must consider them together by row--see my response. Simplest way is as done there to convert to a 1D character vector as the 'rows' option doesn't work for cellstr arrays, unfortunately. (Why not is anybody's guess... :( )
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