How can i shorten the duration this code takes? it takes 0.4 seconds to complete if you insert a longer string. I would prefer not using the for loop but it is still welcome

this code scans a string for letters and ignores repeating letters, for example scans 'xyxzyx' and returns 'xyz' as there are only 3 letters present. the goal is to re-write in a way that takes less time to execute. thanks in advance... here is the code

str='shdydjsgdnsladhdksjkhdjksa'
fixed2=str; %ignore the redundancy

A1=fixed2;
    for i=1:numel(fixed2)
      k=fixed2(i);
      A1=regexprep(A1,'(?<=(??@k).*)(??@k)','')
   end

Answer 1

[Fangjun Jiang]

what about A1=unique(str)?

[Waboraro Olefile]

Thanks Fangjun Jiang! i wasnt aware of the function. you just saved me a great deal of execution time!!