Remove cell that contains strings of another cell array

Input:

a={'Time12:30','Time12:40','Time1:40', 'Time2:40'};
b={'12:', '1:'};

Wanted Output: (delete from "a" all cells containing string listed in "b")

a={'Time2:40'}

I have tried:

for k = 1 : length(a)
  for kk = 1 : length(b)
    if any(~ismember(b{kk}, a{k}))
      a(k) = [];
      break;
    end
  end
end

However this gives me error of such:

Index exceeds matrix dimensions.

I am confused by the error and any guidance is appreciated! Thank you for reading my post.

Answer 1

[James Tursa]

You are changing the size of a in the loop with this line:

      a(k) = [];

So subsequent iteration indexes that depend on the length of a will fail. Maybe save the indexes to delete in the loop, and then delete them all at once at the end. E.g., something like this:

a={'Time12:30','Time12:40','Time1:40', 'Time2:40'};
b={'12:', '1:'};
x = false(size(a)); % <-- Indexes to delete, start out nobody deleted
for k=1:numel(b)
    x = x | ~cellfun(@isempty,strfind(a,b{k})); % <-- Flag the ones that b{k} matches
end
a(x) = []; % <-- Delete all the flagged lines at once

[chlor thanks]

Thank you for your help James!

Answer 2

[Stalin Samuel]

strfind(a, b(kk))%find a string from string array

Answer 3

[Sean Mahnken]

You should be able to just do the k loop backwards:

for k = length(a):-1:1
  for kk = 1 : length(b)
    if any(~ismember(b{kk}, a{k}))
      a(k) = [];
      break;
    end
  end
end