Decrease the least and increase the highest

I have an array

A = [1 -3 -6 10 2 3 7 -1 -9 -3]

B = [1 2 3 4 5 6 7 8 9 10]

1) I want to check the least negative and the highest positive in array A.

2) In the corresponding number in Matrix B, if it is the least negative then multiply the number in B by 10 and if it is the highest positive, then multiply the number in B by 100.

3) Then B = [1 2 3 400 5 6 7 8 90 10]

[Image Analyst]

Are you sure that's what they want? It's kind of ambiguous. You could also assert that the least negative value is the -1, and the most negative value is -9, in which case the 8 would be multiplied by 10 instead of the 9.

[Star Strider]

OP seems to be posting homework problems.

Answer 1

[Star Strider]

A = [1 -3 -6 10 2 3 7 -1 -9 -3];
B = [1 2 3 4 5 6 7 8 9 10];
[~,idxlo] = min(A);
[~,idxhi] = max(A);
B(idxlo) = 10*B(idxlo);
B(idxhi) = 100*B(idxhi)

B =
     1     2     3   400     5     6     7     8    90    10

Answer 2

[Thorsten]

B(A == max(A)) = B(A == max(A))*100;
B(A == min(A)) = B(A == min(A))*10;