How do I print only one element of a char array with same elements?

So, here is the very simple practice code:

clear all
close all
clc
x=1:20;
for i=1:20
    if x(i)<=5
        say=('Hi')
    elseif x(i)>5 && x(i)<=10
        say=('Hello')
    elseif x(i)>10 && x(i)<=15
        say=('How is it going?')
    else
        say=('Fine')
    end
end

I am new to Matlab and I got stuck on a simple point where I need to print any of the answers only once. I know that I'm gonna get 4 different answers 5 times each, but I want to get only one of each answer. One which will stand for the rest of the same answers. For example, just: 'Hi', 'Hello', 'How is it going', 'Fine' instead of getting each of them 5 times. Thanks in advance!

say =
Hi
say =
Hi
say =
Hi
say =
Hi
say =
Hi
say =
Hello
say =
Hello
say =
Hello
say =
Hello
say =
Hello
say =
How is it going?
say =
How is it going?
say =
How is it going?
say =
How is it going?
say =
How is it going?
say =
Fine
say =
Fine
say =
Fine
say =
Fine
say =
Fine
>>

Answer 1

[Azzi Abdelmalek]

x=1:20;
[test1,test2,test3,test4]=deal(0)
for i=1:20
  if x(i)<=5 & test1==0
      say=('Hi')
      test1=1;
  elseif x(i)>5 && x(i)<=10 & test2==0
      say=('Hello')
      test2=1;
  elseif x(i)>10 && x(i)<=15  & test3==0
      say=('How is it going?')
      test3=1;
  elseif test4==0
      say=('Fine')
      test4=1;
  end
end

[Mardan Tahmazli]

oh I see. Does it mean that when you assign test# = 1, it breaks?

   if x(i)<=5 & test1==0
        say=('Hi')
        test1=1;

So basically I can put anything here, right? Like if it was y=5 first, and then y=6.

x=1:20;
y=5
for i=1:20
    if x(i)<=5 & y==5
        say=('Hi')
        y=6;
    elseif x(i)>5 && x(i)<=10 & y==6
        say=('Hello')
        y=7;
    elseif x(i)>10 && x(i)<=15 & y==7
        say=('How is it going?')
        y=8;
    elseif y==8
        say=('Fine')
        y=9;
    end
end

Thank you very much! It is all clear for me now.

[Mardan Tahmazli]

But definitely your method is much better than the one I posted now. Because it might be that the conditions are met in another order, not successively. Then my bit of code will not work. Thank you again!

[Mardan Tahmazli]

Sorry, I got stuck again, because in my code where I tried to apply this method, my requirement is to run it 8000 times, and I need all 8000 iterations. But as soon as I assign task=1, it breaks and it will not continue anymore..is there any other solution I can use? would appreciate a lot!