uniformly distributed coordinate points

can anyone help me to generate uniformly distributed coordinate points inside a rectangular field.

Thanking u advance

Answer 1

[Sarah Wait Zaranek]

You can also do the following if you want a uniform grid:

[X,Y] = meshgrid(linspace(1,1000,100),linspace(1,1000,100));

This will give X coordinates and Y coordinates for each grid point inside a 1000 x 1000 rectangle. The segmenting in terms of x and y are defined by the input vectors, in this case, I am choosing 100 points per side.

scatter(X(:),Y(:))

will show you all the points.

Answer 2

[Andreas Goser]

This sounds like a one-liner with RAND or RANDI for me. Do you run into issues with this command or did you just not find it?

[Basanta]

no, actually I need to generate coordinates from a 1000x1000 meter rectangular field. the coordinates should be uniformly distributed...

plz help...

Answer 3

[Matt Tearle]

xmin = -3;
xmax = pi;
npts = 42;
x = xmin + (xmax-xmin)*rand(npts,1);

Repeat for y.

[Basanta]

after repeating, should I get a uniformly distributed coordinates?

[Matt Tearle]

yes. what i showed generates 42 x-coordinates uniformly distributed between -3 and pi. do the same for y, then scatter(x,y) will show the result.

[Oleg Komarov]

To get all at once:

min = [ 1 1];

max = [10 3];

npts = 1000;

xy = bsxfun(@plus, min, bsxfun(@times, max-min,rand(npts,2)));

f = scatter(xy(:,1),xy(:,2),'.');

xlim([0,11])

ylim([0,4])

[Matt Tearle]

ahahaha. nice :)

Answer 4

[sh]

Hi, thanks for your help. can you find the x-coordinate and y-coordinates of these points by coding only? many thanks

Answer 5

[Edward Goodison]

[X,Y,Z] = meshgrid(linspace(Start,stop, number of points),linspace(Start,stop, number of points), linspace(Start,stop, number of points));
p = [X(:), Y(:), Z(:)]

[Rik]

Why not use [X(:), Y(:), Z(:)] instead of the loop?

[Edward Goodison]

nice, good improvement, will edit.