How to find equation level?

equation of the plane which cuts the axes segments a1, b1, and c1 and then determines the level that coordinates A 'which is the closest point A (a2, b2, c2) and the distance between A and A'. So enter the parameters a1, a2, b1, b2, c1, c2, and as a result gain level equations, the coordinates of points, the distance value and a graphical representation of the position of the plane in point.

I have no idea how to find this.

Answer 1

[Roger Stafford]

The key to solving such a problem is that the point A’ must not only satisfy the equation for the plane (one equation) but the vector A-A’ must be proportional to the normal vector to the plane (two more equations.) The solution to the three equations would give you the coordinates of A’. (Note: you should really designate the unknown point by something different than A’, since that can be confused with matlab’s transpose operator.)