draw min squares in black and white

조회 수: 3 (최근 30일)
Ahmed raafat
Ahmed raafat 2016년 5월 27일
편집: Roger Stafford 2016년 5월 28일
Hi every
I want to plot min squares in black and white like the attachment
I had an idea (I didn't try it that i make the 3-dim image matrices)
Is there other solutions???
  댓글 수: 3
Ahmed raafat
Ahmed raafat 2016년 5월 27일
I mean with like a grid with square size 1cm*1cm
And it is a task
Ahmed raafat
Ahmed raafat 2016년 5월 27일
Please see the attachment to understand me of min squares

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채택된 답변

Roger Stafford
Roger Stafford 2016년 5월 27일
Do the following:
m = 16; n = 33;
A = false(m,n);
A(1,17) = true;
for k = 2:m
v = 2:n-1;
A(k,v) = A(k-1,v-1)~=(A(k-1,v)|A(k-1,v+1));
end
Then use the A(:,2:n-1) matrix to determine which squares are to be black (true) and which are white (false.) I’ll leave the plotting up to you.
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Ahmed raafat
Ahmed raafat 2016년 5월 28일
Thanks mr.Roger
It worked
Roger Stafford
Roger Stafford 2016년 5월 28일
편집: Roger Stafford 2016년 5월 28일
It should be noted here that your “rule 30” presumably refers to a logic method devised by Stephen Wolfram for generating a pseudo-random sequence of binary digits. The “30” refers to the binary representation of the truth table involved: 00011110.

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추가 답변 (1개)

Image Analyst
Image Analyst 2016년 5월 28일
Seems like homework, so here's a hint. Look at the pattern. The three binary squares above are 7, 6, 5, 4, 3, 2, 1, 0. You just need to turn the three elements above the current element into a decimal number like
decNumber = 4*A(row-1, col-1) + 2*A(row-1, col) + A(row-1, col+1);
Then if decNumber is 1 through 4 inclusive, then set the value to 1, otherwise it's zero.

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