How to take first three characters of string
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Hi,
I have the below cell array:
MA0K123T0
MB0JHY210I9
AoTkU08
880KE21L
PMB456KU0
standard
MF0KET9
twist
MA0KL3
PMV09K
Now I want to filter as below:
If the name start with M or P, then take the first three characters otherwise keep original name. My output should be:
MA0
MB0
AoTkU08
880KE21L
PMB
standard
MF0
twist
MA0
PMV
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채택된 답변
Azzi Abdelmalek
2016년 5월 23일
편집: Azzi Abdelmalek
2016년 5월 23일
str={'MA0K123T0'
'MB0JHY210I9'
'AoTkU08'
'880KE21L'
'PMB456KU0'}
out=cellfun(@(x) regexprep(x,'\<(M|P).+',x(1:3)),str,'un',0)
댓글 수: 7
Azzi Abdelmalek
2016년 5월 24일
This doesn't give the expected result (look at the new question in the hidden comment)
Azzi Abdelmalek
2016년 5월 24일
We can use dynamic expressions
match_expr = '(M|P)([a-zA-Z]?)([a-zA-Z]?)(.+)'
replace_expr='$1$2$3'
regexprep(str, match_expr, replace_expr)
추가 답변 (1개)
Guillaume
2016년 5월 23일
편집: Guillaume
2016년 5월 24일
Azzi's answer with to regex call seems unnecessarily complicated to me. The cellfun is also not required. This simple regex will do:
str = {'MA0K123T0'
'MB0JHY210I9'
'AoTkU08'
'880KE21L'
'PMB456KU0'}
out = regexp(str, '^[MP].{2}|.*', 'match', 'once')
Which basically says match M or P (the [MP]) at the beginning of the string (the ^) followed by any two characters (the .{2}) and if that does not match, match everything (the |.*)
edit for your updated question:
out = regexp(str, '^[MP][A-Za-z]?[A-Za-z]?|.*', 'match', 'once')
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