Converting a num2str(a) to letter with Numbers bigger the 27
조회 수: 2 (최근 30일)
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Hello,
I am trying to transfer Data from 30 Days from 30 Excel Tables (one for each day) to a single Excel Table (as a summary). So it is important for me to get the output of "AA", "AB", ... when I reach the higher numbers.
I tried a few different versions, but for some reasons the "Day" variable just changes its number (for example from 1 to 50)
Try 1)
a = 1; b = 30;
while a <= b;
Day = num2str(a);
asciiValue = [Day];
Day_Letter = char(asciiValue);
Save_Group = [Day_Letter Day ':' Day_Letter Day]
a = a + 1;
end
Try 2)
if Day <=25
CharDay = Day;
Day_Letter = char(CharDay)
else
if Day == 26
Day_Letter = 'AA'
else if Day == 27
Day_Letter = 'AB'
else if Day == 28
Day_Letter = 'AC'
else if Day == 29
Day_Letter = 'AD'
else if Day == 30
Day_Letter = 'AE'
end
end
end
end
end
endAnd by now I got desperate and started doing it like this:
Day = num2str(a);
if Day == 1;
Day_Letter = 'B' end
if Day == 2;
Day_Letter = 'C' end
if Day == 3;
Day_Letter = 'D' end
if Day == 4;
Day_Letter = 'E' end
if Day == 5;
Day_Letter + 'F' end
if Day == 6;
Day_Letter = 'G' end
if Day == 7;
Day_Letter = 'H' end
if Day == 8;
Day_Letter = 'I' end
if Day == 9;
Day_Letter = 'J' end
if Day == 10;
Day_Letter = 'K' end
if Day == 11;
Day_Letter + 'L' end
if Day == 12;
Day_Letter = 'M' end
if Day == 13;
Day_Letter = 'N' end
if Day == 14;
Day_Letter = 'O' end
if Day == 15;
Day_Letter = 'P' end
if Day == 16;
Day_Letter = 'Q' end
if Day == 17;
Day_Letter + 'R' end
if Day == 18;
Day_Letter = 'S' end
if Day == 19;
Day_Letter = 'T' end
if Day == 20;
Day_Letter = 'U' end
if Day == 21;
Day_Letter = 'V' end
if Day == 22;
Day_Letter = 'W' end
if Day == 23;
Day_Letter + 'X' end
if Day == 24;
Day_Letter = 'Y' end
if Day == 25;
Day_Letter = 'Z' end
if Day == 26;
Day_Letter = 'AA' end
if Day == 27;
Day_Letter = 'AB' end
if Day == 28;
Day_Letter = 'AC' end
if Day == 29;
Day_Letter + 'AD' end
if Day == 30;
Day_Letter = 'AE' end
댓글 수: 0
답변 (1개)
Walter Roberson
2016년 5월 17일
dayletters = [num2cell(['1':'9', 'A':'Z']), {'AA', 'AB', 'AC', 'AD', AE'}];
...
Day_Letter = dayletters{a};
댓글 수: 0
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