How to create 3d array equivalent to fortran dimension?

Hello all, I have this fortran code

    dimension x(2,m,n)

where m=100, n=40 Now how to convert this into the matlab?

Answer 1

[Jan]

Perhaps you mean:

x = zeros(2, m, n)

[adi kul]

Thank you. It does create 2XmXn array but this gives zeros of the defined size matrix

In fortran this is not the case. Please guide.

[adi kul]

Sorry. This helped me. Thank you. Now I am facing a new issue.

My fortran code says

j=1,m
g(j) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)

How can I do this 3d multiplication in 1d in matlab. If I use this as it is I get size error for g(j) as matlab cosiders it as 1x1 while my t(k,i,j) is a 2xmxn sized matrix.

Answer 2

[Farrukh Mazhar]

this code probably is wrong the correct Fortran code would be like

do k=1,aa

do i=1,n

do j=1,m

g(j) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)

enddo

enddo

enddo

Please change to

for k=1:aa

do i=1:n

do j=1:m

g(k,j,i) = t(k,i,j)*dcos(anglezx) - t(j)*dsin(anglezx)

end

end

end