reordering the data

조회 수: 19 (최근 30일)
kash
kash 2012년 2월 7일
i have values as
D=[1 2 3 4 5 6 7 ]
now i want to reorder the data
D1=[3 4 7 1 2 6 5]this is for example,
i want the order to be changed from D,without using randperm function,please help

채택된 답변

Andreas Goser
Andreas Goser 2012년 2월 7일
What about generating two random numbers as indices and swapping the data of the indices? And then do this in a loop.
clc
D=[1 2 3 4 5 6 7 ]
for k=1:10
x1=randi(length(D));
x2=randi(length(D));
dummy=D(x1);
D(x1)=D(x2);
D(x2)=dummy
end

추가 답변 (3개)

Junaid
Junaid 2012년 2월 7일
Second possible way is
D = [1 2 3 4 5 6 7];
declare any temp variable to have the order of indices. For example.
T = [3 4 7 1 2 6 5];
D1 = D(T);
In given example your indices and values are same, but for different values following code will work.

Jan
Jan 2012년 2월 7일
D.E. Knuth has shown some shuffle methods, e.g.:
D1 = D;
for i = 2:numel(D) % Knuth shuffle in forward direction:
w = ceil(rand * i); % 1 <= w <= i
t = D1(w);
D1(w) = D1(i);
D1(i) = t;
end
This is proven to be unbiased and cheaper than using 2 random numbers for swapping. See also: FEX: RPG-lab.

Sean de Wolski
Sean de Wolski 2012년 2월 7일
Sure:
[~, idx] = sort(rand(size(D)));
D1 = D(idx);

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