# How can I apply lifting scheme to my own wavelet?

조회 수: 1 (최근 30일)
댓글: Shaik Ahmad 2016년 5월 16일
I have implemented and added a bi-orthogonal wavelet function to the wavelet toolbox using wavemngr function. Now I want to apply lifting scheme to that wavelet. When I apply liftwave(wname) function it is showing "Error using liftwave (line 45)Invalid wavelet name".
In the wavenames also I am not getting my wavelet name. Please provide a solution to add my wavelet in the lifting wave.

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### 채택된 답변

Wayne King 2016년 5월 13일
Hi Shaik,
filt2ls is your friend. You use filt2ls with the filters (include both the analysis and synthesis filters) and that will return the lifting scheme. Then, you use that lifting scheme with lwt.
For example:
[LoD,HiD,LoR,HiR] = wfilters('bior3.1');
ls = filt2ls(LoD,HiD,LoR,HiR);
[CA,CD] = lwt(wecg,ls);
##### 댓글 수: 2없음 표시없음 숨기기
Thank you for your response Wayne. I have tried the above function on my wavelet filters
lp = [2, -1, -6, 17, 40, 17, -6, -1, 2]/64;
hp = [-2, 1, 14, -26, 14, 1, -2]/48;
rlp = hp .* [-1 1 -1 1 -1 1 -1]*2;
rhp = lp .* [1 -1 1 -1 1 -1 1 -1 1]*2;
ls = filt2ls(lp,hp,rlp,rhp);
It is showing error like
Error using filters2lp (line 117)
Invalid biorthogonal filters
Error in filt2ls (line 27)
[Ha,Ga,Hs,Gs,PRCond,AACond] = filters2lp('b',LoR,LoD);
Can you please provide me a solution to over come this problem.
I got these filters from the paper titled "New Approach to the Design of Low Complexity 9/7 Tap Wavelet Filters With Maximum Vanishing Moments". Actually in the paper authors have mentioned only analysis and synthesis low pass filters. By using perfect reconstruction conditions I calculated the high pass filters. At the time of calculation I calculated high pass filters mistakenly.
Thank you for pointing the mistake.
I will do the process again and report you after that.

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### 추가 답변 (1개)

Wayne King 2016년 5월 15일
편집: Wayne King 2016년 5월 15일
Where did you get this biorthogonal filter pair? It does not satisfy the criteria for a biorthogonal (wavelet) filter pair. For one example, the product of the Fourier transforms of the lowpass filters at 0 frequency (DC) should be equal to 2.
In your case, it is equal to -2. The sum of elements in your rlp filter is -2.
A couple things you need to ensure are the following, let G_0() and G_1() denote the Fourier transforms of your lowpass filters and H_0() and H_1() denote your highpass filters
G_0(\omega)G_1^*(\omega)+H_0(\omega)H_1^*(\omega) = 2
G_0(\omega)G_1^*(\omega+\pi)+H_0(\omega)H_1^*(\omega+\pi) = 0
where the * denotes the complex conjugate.

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