Why I get different result at Simulink? (Matlab, Simulink)

조회 수: 13 (최근 30일)
Bob
Bob 2016년 4월 23일
댓글: Stefan Raab 2016년 4월 23일
Why I get different results? (Matlab, Simulink)
My problem is that I get different results with Matlab (Transfer Function) and Simulink at closed loop.
Amplitude is different and when I zoom at Simulink's Plot I get this odd irregularity.
Matlab:
Simulink:

채택된 답변

Stefan Raab
Stefan Raab 2016년 4월 23일
Hello,
I suppose that depends on the solver. The documentation of the "step" function describes in the "More About/Algorithms" section, that the sample time is chose automatically, fixed step if I remember correctly. In Simulink however, you might have used a variable step solver (probably ode45), which is more accurate generally. You can also execute the "step" function with a specified sample time, try a really small sample time as 1e-6 or 1e-7 as this should increase the accuracy. The command then would be:
t = 0:1e-6:10;
step(YourSYS,t);
For the documentation on the step function, execute the following command:
web(fullfile(docroot, 'control/ref/step.html'))
Does this yield more accurate results?
Kind regards, Stefan
  댓글 수: 2
Bob
Bob 2016년 4월 23일
Thanks for your answer,
This fixed my problem. Now my results is correct.
%%Simulink Model
t = 0:1e-6:10;
sim('Simulink_Model',t);
Stefan Raab
Stefan Raab 2016년 4월 23일
I'm glad it works now. But I would use the t for the step function, not the Simulink model. The variable step solvers in Simulink are more powerful and now you force to simulate with a fixed step solver. This cannot adjust it's step size in order to achieve better accuracy and it cannot react to zero-crossings.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 General Applications에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by